15k^2+64k+64=0

Solution for 15k^2+64k+64=0 equation:

15k^2+64k+64=0

a = 15; b = 64; c = +64;
Δ = b2-4ac
Δ = 642-4·15·64
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-16}{2*15}=\frac{-80}{30}
=-2+2/3
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+16}{2*15}=\frac{-48}{30}
=-1+3/5
$